Resultant of two forces when angle between them is `60^(@)` is 6 Newton and if angle between forces increased to `120^(@)` then resultant becomes `sqr
Resultant of two forces when angle between them is `60^(@)` is 6 Newton and if angle between forces increased to `120^(@)` then resultant becomes `sqrt(14N)`, then what will be resultant of these two forces when they will per pendicular to each other
A. 10N
B. 5N
C. `5sqrt(2)N`
D. 4N
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Correct Answer - C
`F_(1)^(2)+F_(2)^(2)+F_(1)F_(2)=36`
`F_(1)^(2)+F_(2)^(2)-F_(1)F_(2)=14`
`F=sqrt(F_(1)^(2)+F_(2)^(2))=sqrt(50)=5sqrt(2)`
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