10 ml of a mixture of `C_(2)H_(2)` and CO gas was exploded with 15ml of oxygen. The gases after the reaction had a volume of 17 ml at 298 K calculate

Question

10 ml of a mixture of `C_(2)H_(2)` and CO gas was exploded with 15ml of oxygen. The gases after the reaction had a volume of 17 ml at 298 K calculate

10 ml of a mixture of `C_(2)H_(2)` and CO gas was exploded with 15ml of oxygen. The gases after the reaction had a volume of 17 ml at 298 K calculate volume of oxygen remained after treatment the resulting gas mixture with KOH.

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - 6
mol of `SO_(2) (M) = (12)/(64)g" " , " mol of "SO_(3)(N) = (10)/(80)g" "because(4M)/(N)=((4xx12)/(64))/((10)/(80))=6`

4 views Answered 2023-02-05 15:29