Find the values of non-negative real number `h_1, h_2, h_3, k_1, k_2, k_3` such that the algebraic sum of the perpendiculars drawn from the points `(2

Question

Find the values of non-negative real number `h_1, h_2, h_3, k_1, k_2, k_3` such that the algebraic sum of the perpendiculars drawn from the points `(2

Find the values of non-negative real number `h_1, h_2, h_3, k_1, k_2, k_3` such that the algebraic sum of the perpendiculars drawn from the points `(2,k_1),(3,k_2),*7,k_3),(h_1,4),(h_2,5),(h_3,-3)` on a variable line passing through (2, 1) is zero.

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

Related Questions

A concentration cell `Pt|H_2(g)|HCl(aq)||H_2SO_(4)(aq)|H_2(g)|Pt` is constructed using equal concentration of acids and equal number of moles of `H_2`

2 Answers 5 Views

In the formation of HBr from `H_2` & `Br_2` following mechanism is observed. (A)`Br_2hArr2Br.` Equilibrium step (B)`H_2+Br.toHBr+H.` slow step ( C)`H.

2 Answers 5 Views

Match Matrix `{:("Column I","Column II"),((A)Zn|Zn^(2+)( C)||Zn^(2+)(2C)|Zn,(p)"Spontaneous cell reaction"),((B)H_2(P)|HCl(1N)||H_2SO_4(1N)|H_2(P),(q)

2 Answers 6 Views

Given : `Zn(OH)_2(s) hArr Zn(OH)_2(aq) , K_1=10^(-6)` `Zn(OH)_2(aq) hArr [Zn(OH)]^(+) +OH^(-) , K_2=10^(-7)` `[Zn(OH)]^+(aq) hArr Zn^(+2)+OH^(-) , K_3

2 Answers 4 Views

In the two gaseous reactions (i) and (ii) at `250^@C` (i) `2NO(g)+(1)/(2)O_2(g)hArrNO_2(g)K_1` (ii) `2NO_2(g) hArr2NO(g)+O_2(g),K_2` the equilibrium c

2 Answers 6 Views

Prove that the product of the lengths of the perpendiculars drawn from the points `(sqrt(a^2-b^2),0)`and `(-sqrt(a^2-b^2),0)`to the line `x/a``costhet

2 Answers 4 Views

A variable line passes through a fixed point P. The algebraic sum of the perpendiculars drawn from the points (2,0), (0,2) and (1,1) on the line is ze

2 Answers 5 Views

Locus of the feet of the perpendiculars drawn from either foci on a variable tangent to the hyperbola `16y^2 -9 x^2 = 1` is

2 Answers 5 Views

A point P moves such that sum of the slopes of the normals drawn from it to the hyperbola xy=16 is equal to the sum of ordinates of feet of normals. T

2 Answers 6 Views

Let `|A|=|a_(ij)|_(3xx3) ne0` Each element `a_(ij)` is multiplied by by `k^(i-j)` Let `|B|` the resulting determinant, where `k_1 |A|+k_2 |B| =a` then

2 Answers 4 Views

Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Let the equation of variable line be
`ax+by+c=0 " " (1)`
It is given that
`sum_(i=1)^(6)(ax_(i)+by_(i)+c)/(sqrt(a^(2) + b^(2))) = 0, "where" (x_(i), y_(i)), i=1,2,3,4,5,6 " are given points."`
`rArr a((sum_(i=1)^(6)x_(i))/(6)) + b((sum_(i=1)^(6)y_(i))/(6)) +c =0 " " (2)`
Comparing (1) and (2), we get
`x/((sum_(i=1)^(6)x_(i))/(6))=y/((sum_(i=1)^(6)y_(i))/(6))=1`
`therefore (x,y) -= ((sum_(i=1)^(6)x_(i))/(6), (sum_(i=1)^(6)y_(i))/(6))`
This is the fixed point through which the variable (1) passes.
But it is given that the variable line is passing through the point (2,1).
`" So, "(sum_(i=1)^(6)x_(i))/(6) = 2" and " (sum_(i=1)^(6)y_(i))/(6) = 1`
`rArr (2+3+7+h_(1) + h_(2)+h_(3))/(6) =2 " and " (k_(1) + k_(2) + k_(3) +4+5-3)/(6) = 1`
`rArr h_(1) + h_(2)+h_(3) =0 " and " k_(1) + k_(2) + k_(3) = 0`
`" Since " h_(1), h_(2),h_(3), k_(1), k_(2),k_(3) " are non-negative,"h_(1) = h_(2) =h_(3)=0 and k_(1) =k_(2)=k_(3)=0.`