Locus of the feet of the perpendiculars drawn from either foci on a variable tangent to the hyperbola `16y^2 -9 x^2 = 1` is

Question

Locus of the feet of the perpendiculars drawn from either foci on a variable tangent to the hyperbola `16y^2 -9 x^2 = 1` is

Locus of the feet of the perpendiculars drawn from either foci on a variable tangent to the hyperbola `16y^2 -9 x^2 = 1` is
A. `x^(2)+y^(2)=9`
B. `x^(2)+y^(2)=1//9`
C. `x^(2)+y^(2)=7//144`
D. `x^(2)+y^(2)=1//16`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
`(y^(2))/(1//16)-(x^(2))/(1//9)=1`
Locus will be the auxiliary circle
`x^(2)+y^(2)=(1)/(16)`

5 views Answered 2023-02-05 15:29