Calculate `lamda_(m)^(0)` of oxalic acid, given that
`lamda_(eq)^(0)Na_(2)C_(2)O_(4)=400Omega^(-1)cm^(2)aq^(-1)`
`lamda_(m)^(0)H_(2)SO_(4)=700Omega^(-1)cm^(2)"mole"^(-1)`
`lamda_(eq)^(0)Na_(2)SO_(4)=450Omega^(-1)cm^(2)eq^(-1)`

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1 Answers

`lamda_(m)^(0)H_(2)C_(2)O_(4)=700+800-900=600Omega^(-1)cm^(2)` mole
`lamda_(eq)^(0)=400+(700)/(2)-450`
`(lamda_(m))/(2)=350-50=300`
`lamda_(m)=600`

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