For a reaction `A(g) hArr B(g)` at equilibrium . The partial pressure of B is found to be one fourth of the partial pressure of A . The value of `Delt

Question

For a reaction `A(g) hArr B(g)` at equilibrium . The partial pressure of B is found to be one fourth of the partial pressure of A . The value of `Delt

For a reaction `A(g) hArr B(g)` at equilibrium . The partial pressure of B is found to be one fourth of the partial pressure of A . The value of `DeltaG^(@)` of the reaction `A rarrB` is
A. RT ln `4`
B. `-"RT" ln 4`
C. `"RT" log 4`
D. `-"RT" log 4`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
`A(g) hArr B(g) " " P_(B) = (1)/(4)P_(A) " "P_(A)=4P_(B)`
`K_(P) = (P_(6))/(P_(A)) = (P_(A)//4)/(P_(A)) = (1)/(4)`
At equilibrium , `DeltaG=O`.
`DeltaG^(@) =-RT l nK_(P) =- RTInK_(P) =- RTIn (1)/(4) = RT In 4`

5 views Answered 2023-02-05 15:29