Reaction of `Br_(2)` with `Na_(2)CO_(3)` in aquesous solution gives sodium bromide bromate with evolution of `CO_(2)` gas. The number of sodium bromid

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Reaction of `Br_(2)` with `Na_(2)CO_(3)` in aquesous solution gives sodium bromide bromate with evolution of `CO_(2)` gas. The number of sodium bromid

Reaction of `Br_(2)` with `Na_(2)CO_(3)` in aquesous solution gives sodium bromide bromate with evolution of `CO_(2)` gas. The number of sodium bromide molecules involved in the balanced chemical equation is:

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

`3Na_(2)CO_(3)+3Br_(2) to 5NaBr+NaBrO_(3)+3CO_(2)`

4 views Answered 2023-02-05 15:29