Setup of Born-Haber cycle, calculation lattice energy of `MgO_((s))`. The given that-enthalpy of formation of `MgO_((s))= -602`, sublimation of `Mg_((

Setup of Born-Haber cycle, calculation lattice energy of `MgO_((s))`. The given that-enthalpy of formation of `MgO_((s))= -602`, sublimation of `Mg_((s))=148 , 1^(st) & 2^(nd)` ionization energy of `Mg= 738 & 1450` respectively. For Oxygen bond dissocitation energy `=498, 1^(st)&2^(nd)` electron gain enthalpy `= -141 & 844` respectively (all unit in `kJ "mole"^(-1)`).

Monjur Alahi

7 views

2025-01-04 04:42

1 Answers

Salim Ahmed Kawsar

Correct Answer - `3890 kJ "mole"^(-1)`

7 views Answered 2023-02-05 15:29

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