Diborane is a potentail rocket fuel which undergoes combusion according to the reaction `B_(2)H_(6)(g)+3O_(2)(g)rarrB_(2)O_(3)(s)+3H_(2)O(g)` From the

Question

Diborane is a potentail rocket fuel which undergoes combusion according to the reaction `B_(2)H_(6)(g)+3O_(2)(g)rarrB_(2)O_(3)(s)+3H_(2)O(g)` From the

Diborane is a potentail rocket fuel which undergoes combusion according to the reaction
`B_(2)H_(6)(g)+3O_(2)(g)rarrB_(2)O_(3)(s)+3H_(2)O(g)`
From the following data, calculate the enthalpy change for the combustion of diborane
`2B(s)+(3//2)O_(2)(g)rarrB_(2)O_(3)(s) DeltaH= -1273 kJ mol^(-1)`
`H_(2)(g)+(1//2)O_(2)(g)rarrH_(2)O(1) " "Delta H= -286 kJ mol^(-1)`
`H_(2)O(1)rarrH_(2)O(g)" "DeltaH=44 kJ mol^(-1)`
`2B(s)+3H_(2)(g)rarrB_(2)H_(6)(g)" "Delta H= 36kJ mol^(-1)`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Correct Answer - `-2035 kJ mol^(-1)`
Given reaction can be obtained as follows:
Add
`{:(B_(2)H_(6)(g)rarr2B(s)+3H_(2)(d)" " DeltaH= -36kJ mol^(-1)),(2B(s)+(3//2)O_(2)rarrB_(2)O_(3)(s)" " DeltaH= -1273kJmol^(-1)),(3[H_(2)O(1)rarrH_(2)O(g)]" " DeltaH= 3xx44 kJ mol^(-1)),(3"["H_(9)(s)+(1//2)O_(2)(g)rarrH_(2)O(l)" " DeltaH= -3xx286kJ mol^(-1)),(bar(B_(2)H_(6)(g)+3O_(2)(g)rarrB_(2)O_(3)(s)+3H_(2)O(g) DeltaH= -2035 kJ mol^(-1))):}`