A gaseous sample is generally allowed to do only expansion`//`compression type work against its surroundings The work done in case of an irreversible

A gaseous sample is generally allowed to do only expansion`//`compression type work against its surroundings The work done in case of an irreversible expansion ( in the intermediate stages of expansion`//`compression the states of gases are not defined). The work done can be calculated using
`dw= -P_(ext)dV`
while in case of reversible process the work done can be calculated using
`dw= -PdV` where `P` is pressure of gas at some intermediate stages. Like for an isothermal reversible process. Since `P=(nRT)/(V)`, so
`w=intdW= - underset(v_(i))overset(v_(f))int(nRT)/(V).dV= -nRT ln(V_(f)/(V_(i)))`
Since `dw= PdV` so magnitude of work done can also be calculated by calculating the area under the `PV` curve of the reversible process in `PV` diagram.
In the above problem
A. work done by the gas in `I^(st)` sample `gt` work done by gas in `II^(nd)` sample
B. work done by gas in `II^(nd)` sample `gt` work done by gas in `I^(st)` sample
C. work done by gas in `I^(st)` sample`=` work done by gas in `II^(nd)` sample
D. None of these