What is `Delta U` when `2.0` mole of liquid water vaporises at `100^(@)C`? The heat of vaporisation `(Delta H_("vap".))` of water at `100^(@)C` is `40

Question

What is `Delta U` when `2.0` mole of liquid water vaporises at `100^(@)C`? The heat of vaporisation `(Delta H_("vap".))` of water at `100^(@)C` is `40

What is `Delta U` when `2.0` mole of liquid water vaporises at `100^(@)C`? The heat of vaporisation `(Delta H_("vap".))` of water at `100^(@)C` is `40.66 KJmol^(-1)`.

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

`Delta U= DeltaH-(P_(2)V_(2)-P_(1)V_(1)) ( because V_(2) gt gt V_(1))`
`Delta H-(P_(2)V_(2)) rArrDeltaH-nRT`
`Delta U= 40.66xx2-(2xx8.314xx373)/(1000)=75.12 KJ`

4 views Answered 2023-02-05 15:29