The enthalpy of formation of `H_(2)O(l)` is `-285 KJ mol^(-1)` and enthalpy of neutralization of a stron acid and a strong bas is `-55 KJ mol^(-1)`. What is the enthalpy of formation of `OH^(-)` ions?

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Given that , `{:(,H^(+)(aq),+OH^(-)(aq),rarr,H_(2)O(l)),(Delta_(f)H,0,,,-285 KJ mol^(-1)):}`
`Delta_("neut")H=Delta_(f) H(H_(2)O,l)-Delta_(f)H(OH^(-),aq)`
Hence `Delta H (OH^(-),aq)=Delta_(f)H(H_(2)O,l)-Delta_("neut")H`
`=[-285-(-55)]KJ mol^(-1)= -230 KJ mol^(-1)`

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