The standard heats of formation at 298K for `C Cl_(4)(g),H_(2)O(g),CO_(2)(g) and HCl(g)` are `-25.5,-57.8,-94.1 and -22.1` kcal `mol^(-1)` respectivel

Question

The standard heats of formation at 298K for `C Cl_(4)(g),H_(2)O(g),CO_(2)(g) and HCl(g)` are `-25.5,-57.8,-94.1 and -22.1` kcal `mol^(-1)` respectivel

The standard heats of formation at 298K for `C Cl_(4)(g),H_(2)O(g),CO_(2)(g) and HCl(g)` are `-25.5,-57.8,-94.1 and -22.1` kcal `mol^(-1)` respectively. Calculate `DeltaH_(298)^(@)` for the reaction.
`C Cl_(4)(g)+2H_(2)O(g)toCO_(2)(g)+4HCl(g)`.

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

`DeltaH^(@)=Delta_(f(products))^(@)-DeltaH_(f("reactants"))^(@)`
`=[DeltaH_(f(CO_(2)))^(@)+4DeltaH_(f(HCl))^(@)]-[DeltaH_(f(C Cl_(4)))^(@)+2DeltaH_(f(H_(2)O))^(@)]`
`=[-94.1+4xx(-22.1)]-[-25.5+2xx(-57.8)]`
`=-94.1-88.4+25.5+115.6`
`=182.5+141.1=41.4kcal`

4 views Answered 2023-02-05 15:29