If an electron having kinetic energy `2 eV` is accelerated through the potential difference of `2` volt. Then calculate the wavelength associated with

Question

If an electron having kinetic energy `2 eV` is accelerated through the potential difference of `2` volt. Then calculate the wavelength associated with

If an electron having kinetic energy `2 eV` is accelerated through the potential difference of `2` volt. Then calculate the wavelength associated with the electron

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - `6.15 Å`
Initial kinetic energy `KE=2 ev`
increase in `KE` due to acceleration `=qxxV=exx2v=2eV`
`:.` Fimal kinetic energy, `KE_(f)=2+2=4 eV`.
`:.` Associated de-Broglie wavelength, `lambda=12.27/sqrt(4)=6.15 Å`

7 views Answered 2023-02-05 15:29