A charged particle is accelerated through a potential difference of `24 kV` and acquires a speed of `2xx10^(6)m//s`.It is then injected perpendicularl

Question

A charged particle is accelerated through a potential difference of `24 kV` and acquires a speed of `2xx10^(6)m//s`.It is then injected perpendicularl

A charged particle is accelerated through a potential difference of `24 kV` and acquires a speed of `2xx10^(6)m//s`.It is then injected perpendicularly into a magnetic field of strength `0.2 T`.Find the radius of the circle described by it.

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A::B::C
`qV=1/2mv^(2)`
`qv_(B)=(mv^(2))/r`
`q/m=v^(2)/(2V)=(mv)/(qB)=v/Bxx(2V)/(v^(2))=(2V)/(Bv)=12cm`

5 views Answered 2023-02-05 15:29