A wire of fixed length is wound on a solenoid of length `l` and radius `r`. Its self-inductance is found to be `L`. Now, if the same wire is wound on

Question

A wire of fixed length is wound on a solenoid of length `l` and radius `r`. Its self-inductance is found to be `L`. Now, if the same wire is wound on

A wire of fixed length is wound on a solenoid of length `l` and radius `r`. Its self-inductance is found to be `L`. Now, if the same wire is wound on a solenoid of length `l//2` and radius `r//2` then the self-inductance will be
A. `2 L`
B. `L`
C. `4 L`
D. `8 L`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
`L=(mu_(0)N^(2)pir^(2))/l`
length of wire =`N 2pir`=Constant(=`C`suppose)
`therefore L=mu_(0)(C/(2pir))^(2) (pi r^(2))/l therefore L prop 1/l`
`therefore` Self inductance will become `2L`.

4 views Answered 2023-02-05 15:29