Density of ice is `rho` and that of water is `sigma`. What will be the decrease in volume when a mass `M` of ice melts?

Question

Density of ice is `rho` and that of water is `sigma`. What will be the decrease in volume when a mass `M` of ice melts?

Density of ice is `rho` and that of water is `sigma`. What will be the decrease in volume when a mass `M` of ice melts?
A. `(M)/(sigma-rho)`
B. `(sigma-rho)/(M)`
C. `M[(1)/(rho)-(1)/(sigma)]`
D. `(1)/(M)[(1)/(rho)-(1)/(sigma)]`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
Volume of ice =`(M)/(rho)`, volume of water =`(M)/(sigma)`
`therefore "Change in volume" =(M)/(rho)-(m)/(sigma)=M((1)/(rho)-(1)/(sigma))`

5 views Answered 2023-02-05 15:29