`6.02 xx 10^(21)` molecules of urea are present in 100ml of its solution. The concentration of urea solution is
`6.02 xx 10^(21)` molecules of urea are present in 100ml of its solution. The concentration of urea solution is
A. `0.001 M`
B. `0.01 M`
C. `0.02 M`
D. `0.1 M`
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Correct Answer - D
Moles of urea `= (6.02 xx 10^(21))/(6.02 xx 10^(23)) = (1)/(100)`
Molarity `= (1000)/(100 xx 100) = 0.1 M`
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