A projectile is projected from ground with initial velocity `vecu=u_(0)hati+v_(0)hatj`. If acceleration due to gragvity (g) is along the negative y-direction then find maximum displacement in x-direction.
A. `(u_(0)^(2))/(2g)`
B. `(2u_(0)v_(0))/(g)`
C. `(v_(0)^(2))/(2g)`
D. `(4u_(0)v_(0))/(g)`

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1 Answers

Correct Answer - B
Horizontal range `R=(2u_(x)u_(y))/(g)=(2u_(0)v_(0))/(g)`

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