A body is slipping from an inclined plane of height h and length l . If the angle of inclination is `theta` , the time taken by the body to come from

Question

A body is slipping from an inclined plane of height h and length l . If the angle of inclination is `theta` , the time taken by the body to come from

A body is slipping from an inclined plane of height h and length l . If the angle of inclination is `theta` , the time taken by the body to come from the top to the bottom of this inclined plane is
A. `sqrt((2h)/(g))`
B. `sqrt((2l)/(g))`
C. `(1)/(sin theta)sqrt((2h)/(g))`
D. `sin theta sqrt((2h)/(g))`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
`because (h)/(l)=sin theta rArr l=(h)/(sin theta)`
component of g along l is g `sin theta`
`t=sqrt((2l)/(a))=sqrt((2h)/(sintheta/(g sin theta)))=(1)/(sin theta)sqrt((2h)/(g))`

4 views Answered 2023-02-05 15:29