Two balls are dropped from different heights at different instants. Seconds ball is dropped 2 sec. after the first ball. If both balls reach the groun

Two balls are dropped from different heights at different instants. Seconds ball is dropped 2 sec. after the first ball. If both balls reach the ground simultaneousl after 5 sec. of dropping the first ball. then the difference of initial heights of the two balls will be :- `(g=9.8m//s^(2))`
A. 58.8m
B. 78.4m
C. 98.0m
D. 117.6m

Monjur Alahi

9 views

2025-01-04 04:42

1 Answers

Salim Ahmed Kawsar

Correct Answer - B
`h_(1)-h_(2)=(1)/(2)g(t_(1)^(2)-t_(2)^(2))=(1)/(2)xx9.8(5)^(2)-(3)^(2)`
`=8xx9.5=78.4m`

9 views Answered 2023-02-05 15:29

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