The dimension of the quantity `vecExxvecB`, where `vecE` represents the electric field and `vecB` the magnetic field may be given as

Question

The dimension of the quantity `vecExxvecB`, where `vecE` represents the electric field and `vecB` the magnetic field may be given as

The dimension of the quantity `vecExxvecB`, where `vecE` represents the electric field and `vecB` the magnetic field may be given as
A. `MT^(-3)`
B. `M^(2)LT^(-5)A^(-2)`
C. `M^(2)LT^(-3)A^(-1)`
D. `MLT^(-2)A^(-2)`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Electric field, `E=(F)/(q)=([MLT^(2)])/([AT][:T^(-1)])=[MLT^(-3)A^(-1)]`
Magnetic field, `(F)/(q^(0))=([MLT^(-2)])/([AT][LT^(-1)])=[MT^(-2)A^(-1)]`
`therefore` The dimensions of quantity `vecExxvecB=[MLT^(-3)A^(-1)]`
`[MT^(-2)A^(-1)]=[M^(2)LT^(-5)A^(-2)]`

5 views Answered 2023-02-05 15:29