An electric charge `+q` moves with velocity `vecv=3hati+4hatj+hatk`,in an electromagnetic field given by:
`vecE=3hati+hatj+2hatk` and `vecB=hati+hatj+3hatk`.The `y`-component of the force experienced by `+q` is:
A. `7 q`
B. `5 q`
C. `3 q`
D. `2 q`

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1 Answers

Correct Answer - 1
`vecF=q[vecE+vecvxxvecB]=F_(y)=7q hatj`

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