If the mean of the distribution is 2.6, then the value of y is `{:("Variate x",1,2,3,4,5),("Frequency f of x",4,5,y,1,2):}`
If the mean of the distribution is 2.6, then the value of y is
`{:("Variate x",1,2,3,4,5),("Frequency f of x",4,5,y,1,2):}`
A. 24
B. 13
C. 8
D. 3
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Correct Answer - C
Mean`=(underset(i=1)overset(n)(sum f_(i)x_(i)))/(underset(i=1)overset(n)(sum f_(i)))`
`therefore 2.6=(1xx4+2xx5+3xxy+4xx1+5xx2)/(4+5+y+1+2)`
`implies 31.2+2.6y=28+3y`
`implies 0.4y=3.2`
`implies y=8`
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