Reduction of `117.5 g BCl_(3)` by `H_(2)` in silent electric discharge produces `HCl`, which required `500 mL` of `xM NaOH` for neutralization. Report

Question

Reduction of `117.5 g BCl_(3)` by `H_(2)` in silent electric discharge produces `HCl`, which required `500 mL` of `xM NaOH` for neutralization. Report

Reduction of `117.5 g BCl_(3)` by `H_(2)` in silent electric discharge produces `HCl`, which required `500 mL` of `xM NaOH` for neutralization. Report `x`.

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

`2BCl_(3)+6H_(2)underset("Electric discharge")overset("Silent")toB_(2)H_(6)+6HCl`
one mole , `3` mole
`HCl + NaOHto NaCl+H_(2)O`
`3` moles `3` moles

5 views Answered 2023-02-05 15:29