The enthalpies of neutralization of `NaOH` & `NH_(4)OH` by `HCl` are -13680 Cal and -12270 Cal respectively. What would be the enthalpy change if one

The enthalpies of neutralization of `NaOH` & `NH_(4)OH` by `HCl` are -13680 Cal and -12270 Cal respectively. What would be the enthalpy change if one gram equivalent of `NaOH` is added to one gram equivalent of `NH_(4)Cl` in solution ? Assume that `NH_(4)OH` and `NaCl` are quantitatively obtained.

Monjur Alahi

6 views

2025-01-04 04:42

1 Answers

Salim Ahmed Kawsar

Correct Answer - `-1410` Cal
`NaOH + NH_(4)Cl rarr NaCl + NH_(4)OH " Delta H = ?`
`Delta H = - 13680 - (-12270) = - 1410 Cal`

6 views Answered 2023-02-05 15:29

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