Aniline behaves as a weak base. When `0.1M ,50mL` solution sample of aniline was mixed with `0.2 M ,12.5mL` of solution of `HCl` ,the `pH` of resultin
Aniline behaves as a weak base. When `0.1M ,50mL` solution sample of aniline was mixed with `0.2 M ,12.5mL` of solution of `HCl` ,the `pH` of resulting solution was `8`.Then :
A. `pH` of `0.01 M` solution of anillinium chloride is `5`.
B. `pH` of original solution of anilline is `3.5`.
C. Upon adding the same aniline sample to the above mixture, `pH` of resulting solution becomes `8.48`.
D. Upon adding the same `HCl` sample to the above mixture `pH` of resulting solution becomes `4.59`.
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`{:(,C_(6)H_(5)NH_(2),+,H^(+),rarr,C_(6)H_(5)NH_(3)),(t=0,5,,2.5,,),(t_(eq),2.5,,-,,2.5):}`
`pOH=pK_(a)=14-8=6`
`:.pK_(a)=6`
Now for the solution of `[C_(6)H_(5)NH_(3)^(+)]=0.01M`
`pH=7-(1)/(2)pK_(a)-(1)/(2)logC=7-(6)/(2)-(1)/(2)log(0.01)=5`
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