A straight wire of length l can slide on two parallel plastic rails kept in a horizontal plane with a separation d. The coefficient of friction betwee

Question

A straight wire of length l can slide on two parallel plastic rails kept in a horizontal plane with a separation d. The coefficient of friction betwee

A straight wire of length l can slide on two parallel plastic rails kept in a horizontal plane with a separation d. The coefficient of friction between the wire and the rails is `mu`. If the wire carries a current I, what minimum magnetic field should exist in the space in order to slide the wire on the rails.

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A::B
Minimum required force to overcome friction
`(mumg)/sqrt(1+mu^(2))=Bilsin thetarArrB=(mumg)/(ilsqrt(1+mu^(2) sin theta) )rArrB_(min)=(mumg)/(ilsqrt(1+mu^(2)))`

7 views Answered 2023-02-05 15:29