A uniform chain of length L and mass M overhangs a horizontal table with its two third part n the table. The friction coefficient between the table and the chain is `mu`. Find the work done by the friction during the period the chain slips off the table.
A. `-(1)/(4)muMgL`
B. `-(2)/(9)muMgL`
C. `-(4)/(9)muMgL`
D. `-(6)/(7)muMgL`

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1 Answers

`W=underset(o)overset(2L//3)int-(muMg)/(L)ldl=-(2)/(9)muMgL`

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