A coin is placed `10cm` in front fo a concave mirror. The mirror produces a real image that has diameter `4` times that of the coin. What is the image distance.

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`m = (d_(2))/(d_(1)) = -(v)/(u)`
`rArr -4 = - (v)/(u) rArr v = 4u`
`= 4xx(-10)`
`= -40cm`

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