A string is stretched betweeb fixed points separated by `75.0 cm`. It observed to have resonant frequencies of `420 Hz` and `315 Hz`. There are no oth

A string is stretched betweeb fixed points separated by `75.0 cm`. It observed to have resonant frequencies of `420 Hz` and `315 Hz`. There are no other resonant frequencies between these two. The lowest resonant frequency for this strings is
A. `10.5 Hz`
B. `105 Hz`
C. `1.05 Hz`
D. `1050 Hz`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

Salim Ahmed Kawsar

Correct Answer - 2
`(n + 1) (v)/(2l) = 420 …..(1)`
`(nv)/(2l) = 315 ….(2)`
`(1) - (2) (V)/(mu) = 105 Hz , f_(min) = = 105 Hz`

5 views Answered 2023-02-05 15:29

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