Photoelectric emission is observed from a surface for frequencies `v_(1)` and `v_(2)` of incident radiation `(v_(1)gtv_(2))` If max K.E of photoelectr

Question

Photoelectric emission is observed from a surface for frequencies `v_(1)` and `v_(2)` of incident radiation `(v_(1)gtv_(2))` If max K.E of photoelectr

Photoelectric emission is observed from a surface for frequencies `v_(1)` and `v_(2)` of incident radiation `(v_(1)gtv_(2))` If max K.E of photoelectrons in two cases are in the ratio 1 : k, then threshold frequency `(v_(0))` will be.
A. `(v_(2)-v_(1))/(k-1)`
B. `(kv_(1)-v_(2))/(k-1)`
C. `(kv_(2)-v_(1))/(k-1)`
D. `(v_(2)-v_(1))/(k-1)`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`hv_(1)=hv_(0)+KE_(1)" "......(1)`
`hv_(2)=hv_(0)+KE_(2)" "......(2)`
`(KE_(1))/(KE_(2))=(1)/(K)=(hv_(1)-hv_(0))/(hv_(2)-hv_(0))`
`k(hv_(1)-hv_(0))=hv_(2)-hv_(0)`
`khv_(1)-khv_(0)=hv_(2)-hv_(0)`
`kv_(1)-kv_(0)=v_(2)-v_(0)`
`kv_(1)-v_(2)=(k-1)v_(0)`
`v_(0)=(kv_(1)-v_(2))/((k-1))`

5 views Answered 2023-02-05 15:29