At 100 K, a reaction is `30%` complete in 10 minutes, while at 200 K, 30% is complete in 5 minutes . The activation energy of the reaction is :
A. `2050 J`
B. 4000 J
C. 3000 J
D. 1150 J

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1 Answers

Correct Answer - D
We know:
`log_(10)((k_(2))/(k_(1)))=(E_(a))/(2.303R)xx((1)/(T_(1))-(1)/(T_(2)))`
`log_(2)=(E_(a))/(2.303xx8.314)xx((1)/(100)-(1)/(200))`
`E_(a)=1150 J "mol"^(-1)`

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