The rate constant for a reaction is `1.5 xx 10^(-7)` at `50^(@)`C and `4.5 xx 10^(7)s^(-1)` at `100^(@)`C . What is the value of activation energy?

Question

The rate constant for a reaction is `1.5 xx 10^(-7)` at `50^(@)`C and `4.5 xx 10^(7)s^(-1)` at `100^(@)`C . What is the value of activation energy?

The rate constant for a reaction is `1.5 xx 10^(-7)` at `50^(@)`C and `4.5 xx 10^(7)s^(-1)` at `100^(@)`C . What is the value of activation energy?
A. `2.2 xx 10^(3) J mol^(-1)`
B. `2300 J mol^(-1)`
C. `2.2 xx 10^(4) J mol^(-1)`
D. `220 J mol^(-1)`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
c) `log k_(2)/k_(1) = E_(a)/(2.303R) (T_(2)-T_(1)]/(T_(1)T_(2))`
`(log 4.5 xx 10^(7))/(log 1.5 xx 10^(7)) = E_(a)/(2.303 xx 8.314) xx [(373-323)/(373 xx 323)]`
log3 `= (E_(a) xx 50)/(2.303 xx 8.314 xx 19.147 xx 373 xx 323)`
`E_(a) = 22011 J mol^(-1)=2.2 xx 10^(4) J mol^(-1)`

4 views Answered 2023-02-05 15:29