A first order reaction has half life of `14.5` hrs. What percentage of the reactant will remain after 24 hrs ?
A first order reaction has half life of `14.5` hrs. What percentage of the reactant will remain after 24 hrs ?
A. `18.3%`
B. `31.8%`
C. `45.5%`
D. `68.2%`
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`k=(2.303)/(t)log((a)/(a-x))`
`(0.693)/(14.5)=(2.303)/(24)log.(100)/((a-x))`
On solving `(a-x) =31.8%`
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