The half life period of a first order chemical reaction is `6.93` minutes. The time required for the completion of `99%` of the reaction will be `(log2=0.301)`
A. `230.3` minutes
B. `23.03` minutes
C. `46.06` minutes
D. `460.6` minutes.

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1 Answers

Correct Answer - C
c) `t=(2.303)/k log a/(a-x)`
`=((2.303) xx (6.93))/(0.693) log 100/1`
`(2.303 xx 6.93 xx 2)/(0.693)`
`=46.06` minutes.

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