`Al^(3+)(aq) + 3e^(-) rightarrow Al(s)` `E^(@) = -1.66V` `Cu^(2+)(aq) + 2e^(-) rightarrow Cu(s)` `E^(@) = +0.34V` What voltage is produced under stand
`Al^(3+)(aq) + 3e^(-) rightarrow Al(s)` `E^(@) = -1.66V`
`Cu^(2+)(aq) + 2e^(-) rightarrow Cu(s)` `E^(@) = +0.34V`
What voltage is produced under standard conditions by combining the half-reactions witih these standard Electrode Potential?
A. 1.32 V
B. 2.00 V
C. 2.30 V
D. 4.34 V
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Correct Answer - B
The cell will be
`Al (s) |Al^(3+) (aq.)|| Cu^(2+) (aq.) | Cu(s)`
`E_("Cell")^(@) = E_("Cathode")^(@) - E_("Anode")^(@)`
`= E_(Cu^(2+)//Cu)^(@) - E_(Al^(3+) // Al)^(@)`
`= +0.34 - (- 1.66) = + 2.00 V`
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