02. If \( a, b \), c ane anequal no in HP, the find \[ \Rightarrow \frac{a+b}{2 a-b}+\frac{c+b}{2 c-b} b= \]
02. If \( a, b \), c ane anequal no in HP, the find \[ \Rightarrow \frac{a+b}{2 a-b}+\frac{c+b}{2 c-b} b= \]
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Given a, b, c are in HP.
So b = 2ac/(a+b) …(i)
(a+b)/(2a-b) + (c+b)/(2c-b) = (substitute the value of b)
= a+(2ac/(a+b))/(2a – 2ac/(a+c)) + (c + 2ac/(a+c))/(2c – 2ac/(a+c))
By solving above equation, we get 1+ (3/2)(c/a + a/c)
= 1+ (3/2)(a2 + c2 -2ac + 2ac)/ac
= 1+ (3/2)((a-c)2/ac) + 3
= 4 + (3/2)((a-c)2/ac)
≥ 4
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