An electric current passing for 6 minutes through a dilute `H_(2)SO_(4)` solution gave 40 mL of the electrolytic gas `(H_(2)+O_(2))`meausred at NTP. W

Question

An electric current passing for 6 minutes through a dilute `H_(2)SO_(4)` solution gave 40 mL of the electrolytic gas `(H_(2)+O_(2))`meausred at NTP. W

An electric current passing for 6 minutes through a dilute `H_(2)SO_(4)` solution gave 40 mL of the electrolytic gas `(H_(2)+O_(2))`meausred at NTP. What was the average value of current ?

Monjur Alahi

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2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - 0.638 ampere
96500 coulomb give 11.2 litre of `H_(2)` and 5.6 litre of `O_(2)` i.e., 16.8 litre of electrolytic gas at NTP.

4 views Answered 2023-02-05 15:29