If origin is the centroid of a triangle, whose vertices are (3, 2), (-6, y) and (3,-2), then y = ………………….
If origin is the centroid of a triangle, whose vertices are (3, 2), (-6, y) and (3,-2), then y = ………………….
A) 0
B) 3
C) 2
D) 6
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Correct option is (A) 0
Vertices of triangle are (3, 2), (-6, y) and (3,-2).
\(\therefore\) Centroid of triangle \(=\left(\frac{3+(-6)+3}3,\frac{2+y+(-2)}3\right)\)
\(=(0,\frac y3)\)
But given that centroid of triangle is origin (0, 0).
\(\therefore\) \((0,\frac y3)=(0,0)\)
\(\Rightarrow\frac y3=0\) (By comparing y-coordinate)
\(\Rightarrow y=0\)
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