If the vertices of a triangle are `(sqrt5,0)` and `(sqrt3,sqrt2)`, and `(2,1)` then the orthocentre of the triangle is

Question

If the vertices of a triangle are `(sqrt5,0)` and `(sqrt3,sqrt2)`, and `(2,1)` then the orthocentre of the triangle is

If the vertices of a triangle are `(sqrt5,0)` and `(sqrt3,sqrt2)`, and `(2,1)` then the orthocentre of the triangle is
A. `(sqrt5,0)`
B. `(0,0)`
C. `(sqrt5+sqrt3+2,sqrt2+1)`
D. none of these

Monjur Alahi

8 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - C
The circumcenter of the triangle is (0,0) as vertices are at equal distance from (0,0). So, the orthocenter will be (sum of x-coordinates, sum of y-coordinates).

8 views Answered 2023-02-05 15:29