For a particle executing (SHM) the displacement (x) is given by `(x = A) cos (omega) t`. Identify the graph which represents the variation of potential energy (PE) as a function of time (t) and displacement (x).
A. `I, III`
B. `II, IV`
C. `II, III`
D. `I, IV`

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Correct Answer - A
Potential energy is minimum (in this case zero) at mean position `(x = 0)` and maximum at extreme position `(x = +-A)`.
At time `t = 0, x= A` Hence, PE should be maximum. Therefore, graph is correct. Further is graph III. PE is minimum at ` x= 0`. Hence this is also correct.

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