The acceleration due to gravity at height `R` above the surface of the earth is `g/4`. The periodic time of simple pendulum in an artifical satellie at this height will be :-
A. `T = 2pisqrt((2l)/(g))`
B. `T = 2pisqrt((l)/(2g))`
C. zero
D. infinity

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1 Answers

Correct Answer - D
In an artificial satellite
`g_(eff) = 0 rArr T = oo`

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