The radius of electron orbit and the speed of electron in the ground state of hydrogen atom is `5.30xx10^(-11)m` and `22xx10^(6)m s^(-1)` respectively

Question

The radius of electron orbit and the speed of electron in the ground state of hydrogen atom is `5.30xx10^(-11)m` and `22xx10^(6)m s^(-1)` respectively

The radius of electron orbit and the speed of electron in the ground state of hydrogen atom is `5.30xx10^(-11)m` and `22xx10^(6)m s^(-1)` respectively, then the orbital peroid of this electron in second excited state will be
A. `1.21xx10^(-14)s`
B. `1.21xx10^(-12)s`
C. `1.21xx10^(-10)s`
D. `1.21xx10^(-15)s`

Monjur Alahi

9 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
Here, `r_1=5.30xx10^(-11)m,v_1=2.2xx10^6ms^(-1)`
In the second excited state, `r_n=n^2r_1,v_n=(v_1)/(n)`
`therefore r_2=4r_1=4xx5.30xx10^(-11)m=2.12xx10^(-10)m` and `v_2=(v_1)/(2)=(2.2xx10^(6))/(2)ms^(-1)=1.1xx10^(6)ms^(-1)`

9 views Answered 2023-02-05 15:29