The angular speed of the electron in the `n^(th)` Bohr orbit of the hydrogen atom is proportional to

Question

The angular speed of the electron in the `n^(th)` Bohr orbit of the hydrogen atom is proportional to

The angular speed of the electron in the `n^(th)` Bohr orbit of the hydrogen atom is proportional to
A. directly proportional to n
B. inversely proportional to `sqrt(n)`
C. inversely proportional to `n^2`
D. inversely proportional to `n^3`

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - D
`omega=(v)/(r).`Further `vprop(1)/(n)` and `rpropn^2`. Hence `omegaprop(1//n^3)`

4 views Answered 2023-02-05 15:29