A string of length L and mass M is lying on a horizontal table. A force F is applied at one of its ends. Tension in the string at a distance x from the end at which force is applied is
A. Zero
B. F should be equal to the weight of A and B
C. F(L-x)/L
D. F(L-x)M

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Correct Answer - C
`T=(M)/(L)(L-x)x(F)/(M)`

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