A 150 g ball, moving horizontally at 20m/s was hit straight back to bowler at 12m/s. If contact with bat lasted for 0.04 sec, then average force exerted by the bat on the ball is:-
A. 100N
B. 120N
C. 150N
D. 200N

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1 Answers

Correct Answer - B
`(0.15(20+12))/(0.04)=(12xx32)/(4)=120N`

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