0.1914 g of an organic acidi s dissolved in about 20 ml of water. 25 ml of 0.12 N NaOH is required for the complete neutralizatioonf the acid solution. The equivalent weight of the acid is
A. `65.0`
B. `64.0`
C. `63.8`
D. `62.5`

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1 Answers

Correct Answer - C
25 mL of 0.12 N NaOH `rarr`0.1914 g acid
`therefore " 1000 mL of 1 N NaOH "=(0.914xx1000)/(25xx0.12)=63.8`
Hence Eq.wt of acid =63.8.

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