Statement-1:Potassium chromate solution in acetic acid precipitates only `Ba^(2+)` as `BaCrO_4` in group `V^(th)` Statement-2:`SrCrO_4 and CaCrO_4` ar

Question

Statement-1:Potassium chromate solution in acetic acid precipitates only `Ba^(2+)` as `BaCrO_4` in group `V^(th)` Statement-2:`SrCrO_4 and CaCrO_4` ar

Statement-1:Potassium chromate solution in acetic acid precipitates only `Ba^(2+)` as `BaCrO_4` in group `V^(th)`
Statement-2:`SrCrO_4 and CaCrO_4` are not precipitated with potassium chromate solution in acetic acid.
A. Statement-1 is True, Statement-2 is True, Statement-2 is a correct explanation for Statement-1
B. Statement-1 is True, Statement-2 is True, Statement-2 is NOT a correct explanation for Statement-1
C. Statement-1 is True, Statement-2 is False.
D. Statement-1 is False, Statement-2 is True.

Monjur Alahi

4 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - B
`K_(sp)` of `SrCrO_4` and `CaCrO_4` are much higher than `BaCrO_4`. Addition of acetic acid lowers the concentration of `CrO_4^(2-)`.Hence `BaCrO_4` is precipitated only because its `K_(sp)` value is lower.

4 views Answered 2023-02-05 15:29