The energy released by the fission of one uranium atom is 200 MeV. The number of fission per second required to prodice 6.4W power is

Question

The energy released by the fission of one uranium atom is 200 MeV. The number of fission per second required to prodice 6.4W power is

The energy released by the fission of one uranium atom is 200 MeV. The number of fission per second required to prodice 6.4W power is
A. `2xx10^(11)`
B. `10^(11)`
C. `10^(10)`
D. `2xx10^(10)`

Monjur Alahi

5 views

2025-01-04 04:42

1 Answers

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Salim Ahmed Kawsar · Accepted Answer · 2023-02-05T15:29:48+06:00

Salim Ahmed Kawsar

Correct Answer - A
(a) Let there is n number of fission per second produces a power of 6.4 W, then
`nxx200x10^(6) xx16x10^(-19) Js^(-1) =6.4Js^(-1)`
`therefore n=(6.4)/( 200xx10^(-13) xx1.6)=(4)/(2xx10^(-11))=2xx10^(11)`

5 views Answered 2023-02-05 15:29